Respuesta :

Catya
23. similar triangles can be solved with ratios.

50/110 = (FQ)/176
176 * 50/110 = (FQ)
80 = (FQ)
side FQ = 80

25.
10/15 = x/9
9 * 10/15 = x
6 = x

Whole side is:  6 + 9 = 15