Explanation: No fraction can have a denominator = 0 because this would make it undefined. Therefore, the solution would be all the real values except for those that make the denominator = 0 Let's check the terms in the denominator: i. c-3 = 0 at c = 3 ii. c = 0 iii. c(c-3) = 0 at c = 0 or c = 3 Therefore 0 and 3 are the values that would make the denominator zero.
Based on the above, the solution is all real numbers except 0 and 3
