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. When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of Ca3(PO4)2? Ca(OH)2 + H3PO4 yields H2O + Ca3(PO4)2 1 2 3 6

Respuesta :

jcherry99
2H3PO4 + 3Ca(OH)2 ===>>>  6 H20 + Ca3(PO4)2

Answer
1 <<<<<=====

Answer: Option (a) is the correct answer.

Explanation:

An equation can only be balanced when number of reactants equal the number of products.

The given equation is as follows.

   [tex]Ca(OH)_{2} + H_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + H_{2}O[/tex]

The number of reactant atoms are as follows.

  • Ca = 1
  • O = 6
  • H = 5
  • P = 1

The number of product atoms are as follows.

  • Ca = 3
  • O = 9
  • H = 2
  • P = 2

To balance the equation, multiply [tex]Ca(OH)_{2}[/tex] by 3, and [tex]H_{3}PO_{4}[/tex] by 2 on the reactant side. Multiply [tex]H_{2}O[/tex] by 6 on the product side. Therefore, the equation will be as follows.

[tex]3Ca(OH)_{2} + 2H_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + 6H_{2}O[/tex]

Thus, we can conclude that the coefficient in front of [tex]Ca_{3}(PO_{4})_{2}[/tex] is 1.

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