Answer: FALSE:
Explanation:
A reaction requires 22.4l of at STP. You have 32.0l of gas at 398k and 105.6 kpa.
1) STP stands for standard temperature and pressure.
2) Standard temperature is 0°C or 273.15 K
3) Standard pressure is 1 atm or 1013.25 kPa
4) use the ideal gas equation for both contidions
pV = n RT
=> n * R = pV /T
at STP n * R = 1031.25 kPa * 22.4 liter / 273.15 K = 84.5
at T = 398 K, p = 105.6 kPa, and V = 3.2.0 liter:
n * R = 105.6 kPa * 32.0 liter / 398 K = 8.49
Since R is a constant (the Universal Gases Constant), it is evident that the number of moles in the 32.0 liter of gas, at T = 398 K and P = 105.6 kPa is less than the number of moles of the 22.4 liter gas at STP.
There is not enough gas to carry out the reaction.
