Using the Equation of Linear Expansion, we have:
[tex]\Delta L =L_{o}. \alpha .\Delta T \\ L-L_{o}=0,125.19.10^{-6}.(200-100) \\ L=2,375.10^{-6}.10^2+0,125 \\ \boxed {L=0,1252375m}[/tex]
Obs: If you notice any mistake in English, please let me know, because I'm not native.