Respuesta :
One number is x.
The other number is 2 more than 3 times the first number, so it's 3x+2.
The sum of the numbers is 22.
[tex]x+3x+2=22 \\ 4x=22-2 \\ 4x=20 \\ x=\frac{20}{4} \\ x=5 \\ \\ 3x+2=3 \times 5+2=15+2=17[/tex]
The numbers are 5 and 17.
The other number is 2 more than 3 times the first number, so it's 3x+2.
The sum of the numbers is 22.
[tex]x+3x+2=22 \\ 4x=22-2 \\ 4x=20 \\ x=\frac{20}{4} \\ x=5 \\ \\ 3x+2=3 \times 5+2=15+2=17[/tex]
The numbers are 5 and 17.
The correct numbers would be 5 and 17 as 17 is two more than 3 times of 5 and their sum is 22.
Let us assume x is the first number then,
Given:
First number = x
second number = 3x+2
The sum of both numbers: 22
Solution:
first no. -- x
2nd no. -- 3x+2
3x+2 + x = 22
4x = 20
x = 5 and
the second number is - 3×(5)+2
So the first number is 5, the other 17
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