The mother and daughter together have 37 years. Two years ago, the mother had 10 years more than the daughter. How old are the mother and daughter now?

FORM A SYSTEM PLS IM IN HURRY

Respuesta :

Answer:

d = 12.5

m = 24.5

Step-by-step explanation:

m = mother

d = daughter

m + d = 37

(m - 2) = (d) + 10

m = d + 12

d + 12 + d = 37

2d = 25

d = 12.5

m = 24.5

Answer:

The system of equations is

M + D = 37
M - D = 10
where M = mother's current age, D = daughter's current age

The solution results in M = 47/2 and D = 27/2

Step-by-step explanation:

Let age of mother be M, age of daughter be D

Now their combined ages = 37

Therefore
M + D = 37


2 years ago, mother and daughter were 2 years younger i.e. M-2 and D-2 ages

Given M-2 = 10 + (D-2)

we get
M - 2 = 10 + d - 2
M - 2 = D + 8
M = D + 8 + 2
M = D + 10
M - D = 10

We have two equations:
M + D = 37
M - D = 10

Adding these two equations together -D and +D cancel out giving

M + M = 37 + 10
2M = 47
M = 47/2

D = 37-47/2 = 74/2 - 47/2 = 27/2