In the triangle below, what ratio is sin θ?

Answer: The required ratio is [tex]\dfrac{12}{13}.[/tex]
Step-by-step explanation: In the given triangle, we are to find the ratio of sinθ.
We know that
in a right-angled triangle, the ratio sine of an angle is given by the length of the perpendicular divided by the length of the hypotenuse.
For the given right-angled triangle, we get
[tex]\sin\theta=\dfrac{perpendicular}{hypotenuse}\\\\\\\Rightarrow \sin\theta=\dfrac{36}{39}\\\\\\\Rightarrow \sin\theta=\dfrac{12}{13}.[/tex]
Thus, the required ratio is [tex]\dfrac{12}{13}.[/tex]