Respuesta :
Answer:
Clifford will run out of bows during the sixth half-hour of his shift
Step-by-step explanation:
Clifford uses 12 bows in the first half-hour, 9 bows in the second half-hour, 14 bows in the third half-hour, and 11 bows in the fourth half-hour, for a total of 12 + 9 + 14 + 11 = <<12+9+14+11=46>>46 bows used.
He has 100 bows and has used 46 bows, so he has 100 - 46 = <<100-46=54>>54 bows left.
If he uses 16 bows during the fifth half-hour, then he will have 54 - 16 = <<54-16=38>>38 bows left.
If he continues to use 16 bows per half-hour, then he will run out of bows during the 38 / 16 = <<38/16=2.375>>2.375 half-hours.
This means that Clifford will run out of bows at around the 2 and 3/8 half-hour mark, or around 2.375 * 30 minutes = <<2.375*30=71.25>>71.25 minutes into his shift.
Since a half-hour is 30 minutes, this means that Clifford will run out of bows at around 5:00 a.m. + 71.25 minutes = <<5+71.25=76.25>>76.25.
This means that Clifford will run out of bows during the 76.25 / 60 = <<76.25/60=1.27>>1.27 hours into his shift, or around the 1 and 1/4 hour mark.
Thus, Clifford will run out of bows during the sixth half-hour of his shift.
Answer:
Eighth half-hour
Step-by-step explanation:
Given pattern:
- 1st half hour = 12 bows used
- 2nd half hour = 9 bows used
- 3rd half hour = 14 bows used
- 4th half hour = 11 bows used
- 5th half hour = 16 bows used
Calculate the differences between the number of bows used:
[tex]12\underbrace{}_{-3}9\underbrace{}_{+5}14\underbrace{}_{-3}11\underbrace{}_{+5}16[/tex]
Therefore, the pattern for the bows used is:
- -3, +5, -3, +5, etc...
If the pattern continues:
[tex]12\underbrace{}_{-3}9\underbrace{}_{+5}14\underbrace{}_{-3}11\underbrace{}_{+5}16\underbrace{}_{-3}13\underbrace{}_{+5}18\underbrace{}_{-3}15\underbrace{}_{+5}20[/tex]
- 6th half hour = 16 - 3 = 13 bows used
- 7th half hour = 13 + 5 = 18 bows used
- 8th half hour = 18 - 3 = 15 bows used
- 9th half hour = 15 + 5 = 20 bows used
Create a table with the given and found data, and add a cumulative total column:
[tex]\begin{array}{c|c|c}\vphantom{\dfrac12} \textsf{Half Hour} & \textsf{Bows used per half hour} & \sf Cumulative\; total\\\cline{1-3} \vphantom{\dfrac12} \sf 1st & 12 & 12\\\vphantom{\dfrac12} \sf 2nd &9 &21 \\\vphantom{\dfrac12} \sf 3rd & 14&35 \\\vphantom{\dfrac12} \sf 4th & 11& 46\\\vphantom{\dfrac12} \sf 5th & 16& 62\\\vphantom{\dfrac12} \sf 6th & 13& 75\\\vphantom{\dfrac12} \sf 7th &18 & 93\\\vphantom{\dfrac12} \sf 8th & 15& 108\\\vphantom{\dfrac12} \sf 9th & 20& 128\\\end{array}[/tex]
If Clifford has a total of 100 bows, he will run out of bows during the eighth half-hour.