Answer
a. 74.2
Explanation
Given that:
The initial temperature, T₁ = 63.2 °C + 273 = 336.2 K
Initial pressure, P₁ = 57.3 kPa
The final volume, V₂ = 15.56 mL
Final temperature, T₂ = 138.7°C + 273 = 411.7 K
Final pressure, P₂ = 334.6 kPa
What to find:
The initial volume, V₁.
Step-by-step solution:
The initial volume, V₁ can be calculated using the combined gas law equation.
[tex]\begin{gathered} \frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} \\ \\ V_1=\frac{P_2V_2T_1}{P_1T_2}=\frac{334.6kPa\times15.56mL\times336.2K}{57.3kPa\times411.7K} \\ \\ V_1=\frac{1750383.611\text{ }mL}{23590.41}=74.2\text{ }mL \end{gathered}[/tex]Hence, its initial volume at 63.2 °C and 57.3 kPa is 74.2 mL
