given the tableau, circle the pivot and explain how you found it

The equations are
[tex]2x_1+3x_2+6x_3+S_2=22[/tex][tex]3x_1+5x_2+3x_3+S_1=20_{}[/tex][tex]-3x_2-1x_3+S_1+Z\text{ = 24}[/tex]The smallest negative number is the pivot column
so the smallest negative number is -3 and hence the pivot column is
3
5
-3
The row pivot hence = 5
so pivot will be (x= -3 and S = 5)