The given expression is,
[tex]4\frac{1}{4}+\frac{7}{8}[/tex]So, this can be solved as,
[tex]\begin{gathered} \frac{4\times4+1}{4}+\frac{7}{8}=\frac{17}{4}+\frac{7}{8} \\ \rightarrow\frac{8\times17+4\times7}{8\times4}=\frac{164}{32}=\frac{41}{8} \end{gathered}[/tex]Explanations:
To solve the mixed fraction,
[tex]4\frac{1}{4}\rightarrow\frac{(4\times4)+1}{4}=\frac{17}{4}[/tex]So, now we are adding the terms, as given in the expression,
[tex]\frac{17}{4}+\frac{7}{8}=\frac{(8\times17)+(7\times4)}{4\times8}[/tex]Here we are employing the rule,
[tex]\frac{a}{b}+\frac{c}{d}=\frac{ad+cb}{bd}[/tex]