The value of the function is h(w - 5) = w^2 - 11w +25
The function is given as:
h(y) = y^2 - y - 5
Substitute w - 5 for y
h(w - 5) = (w - 5)^2 - (w - 5) - 5
Expand the equation
h(w - 5) = w^2 - 10w + 25 - w + 5 - 5
Evaluate the like terms
h(w - 5) = w^2 - 11w +25
Hence, the value of the function is h(w - 5) = w^2 - 11w +25
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