Respuesta :

Using derivatives, the equation of the tangent line is: y + 2= -(x + 2)

What is the equation to the tangent line of a function f(x) at point (x0, y0)?

The equation is:

[tex]y - y_0 = m(x - x_0)[/tex]

In which m is the derivative at point [tex](x_0, y_0)[/tex].

The function is:

[tex]x^2 + y^2 = 8[/tex].

Applying implicit differentiation, the derivative is:

[tex]2x\frac{dx}{dx} + 2y\frac{dy}{dx} = 0[/tex]

[tex]2ym = -2x[/tex]

[tex]m = -\frac{x}{y}[/tex]

We have that x = y = -2, hence m = -1 and the equation is:

y + 2= -(x + 2)

More can be learned about the equation of a tangent line at https://brainly.com/question/22426360

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