In the electrolysis of water, how long will it take to produce 115.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 121.0 mA

Respuesta :

It will take 2273 h.

Here, the ideal gas equation is used.

What is the ideal gas law?

According to the ideal gas law, a gas's pressure is directly proportional to its volume and temperature.

[tex]PV = nRT\\[/tex]

where,

P = Pressure

V = Volume

n = No. of moles

R = Ideal gas constant

T = Temperature

Given,

V = 115.0 L

P = 1 atm

T = 273 K

I = 121 mA

R = 0.0821 atm. L/mol.K

Put the values in the above formula

[tex]n = \frac{PV}{RT}[/tex]                            

  [tex]= \frac{1(115)}{(0.0821) (273)}[/tex]

  [tex]= 5.13 mol[/tex]

The equation says,

2H⁺ + 2e⁻ → H₂

no. of electrons = 2

1 mol of the electron produces a 96500 C charge

5.13 mol of electrons will give = 5.13 × 2 × 96500

                                                  = 990,090 C

I = 121 mA = 0.121 C/s    (1mA = 0.001 C/s)

We know,

q = It

where,

q = charge

I = current

t = time

t = q/I

t = 990,090/ 0.121

t = 8182562 s

t = 2273 h

Therefore, it will take 2273 h.

Learn more about the ideal gas law here:

https://brainly.com/question/6534096

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