Respuesta :
The force between two charged objects if you reduce the distance between two objects from 30 cm to 10 cm. The force will become 100 times less than the initial force.
What is coulombs law?
According to coulombs law force between two charges is given by
[tex]F = \dfrac{1}{4\pi \epsilon }\dfrac{Qq}{r^2}[/tex]
Here, R is the distance between both the charges Q and q.
Let the force on the charges be F1
The distance of separation = r
The magnitudes of the charges q1 and q2
K = Coulumb's constant
[tex]F = \dfrac{1}{4\pi \epsilon }\dfrac{Qq}{r^2}[/tex]
[tex]F = \dfrac{1}{4\pi \epsilon }\dfrac{Qq}{30^2}\\\\F = \dfrac{1}{900}\dfrac{1}{4\pi \epsilon }{Qq}[/tex]
Let the force on the charges be F
The distance of separation = r
The magnitudes of the charges q1 and q2
K = Coulumb's constant
Hence;
[tex]F = \dfrac{1}{4\pi \epsilon }\dfrac{Qq}{r^2}[/tex]
[tex]F = \dfrac{1}{4\pi \epsilon}\dfrac{Qq}{10^2}\\\\F =\dfrac{1}{100} \dfrac{1}{4\pi \epsilon }Qq[/tex]
The force will become 100 times less than the initial force.
Learn more about coulombs law;
https://brainly.com/question/13106909
#SPJ4
