[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Here we go ~
There are 4 carbon atoms in the chain, so it's prefix should be " But " and there are only sigma bonds, therefore the primary suffix will be " ane ", and the functional group attached to the end is " OH " denoting alcohol group, so the secondary suffix will be " ol "
Hence, the name of the compound will be ~
[tex]\qquad \sf \dashrightarrow \:Butan - 1 - ol[/tex]
or simply
[tex]\qquad \sf \dashrightarrow \: Butan ol[/tex]