Respuesta :

SupremeStrange

Answer:

  • Given:-

Side length ( perpendicular = 60 cm)

Hypotenuse = 61 cm

  • To find :-

Base length

  • Solution:

By Pythagoras theorem ,

Hypotenuse² = Perpendicular² + Base²

61² = 60² + base²

3721-3600 = Base²

√121 = base

11cm = base

TheAmethyst

Answer:

  • Base = x = 11 cm

Step-by-step explanation:

In the question we are given ,

  • Side length ( Perpendicular ) = 60 cm

  • Hypotenuse = 61 cm

And we have asked to find the length of base that is denoted by x .

Solution : -

According to Pythagoras Theorem ,

[tex] \longrightarrow \purple{\boxed{H {}^{2} = P {}^{2} + B {}^{2} }} \longleftarrow[/tex]

Where ,

  • H = Hypotenuse

  • P = Perpendicular

  • B = Base

Now , substituting value of hypotenuse, perpendicular and base :

[tex] \hookrightarrow \: 61 {}^{2} = 60 {}^{2} + x {}^{2} [/tex]

Now by squaring 61 and 60 , we get :

[tex] \hookrightarrow \:3721 = 3600 + x {}^{2} [/tex]

Now transposing 3600 to left hand side :

[tex] \hookrightarrow \:3721 - 3600 = x {}^{2} [/tex]

Now subtracting 3600 from 3721 :

[tex] \hookrightarrow \:121 = x {}^{2} [/tex]

[tex] \hookrightarrow \: \sqrt{121} = x[/tex]

We know that 11 × 11 is equal to 121 that means square root of 121 is 11 . So :

[tex] \hookrightarrow \: \red{ \boxed{11 \: cm = x}}[/tex]

  • x = base

  • Henceforth, length of base of right triangle is 11 cm .

#Keep Learning

Otras preguntas