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One popular activity that tourists participate in when they visit Alaska is panning for gold. A gift shop by
the panning center sells blocks of clay. The packaging on the clay claims that one in five blocks contains
gold. A frequent purchaser of this item believes that this is an overstatement. To investigate, he
purchases a random sample of 50 blocks from the large display in the store and finds that 8 of the blocks
contain gold


Based on this sample, is there convincing evidence that the true proportion of blocks that contain gold is
less than 0.20? Use a = 0.10. Provide statistical evidence to support your answer.

HELP QUICK PLS One popular activity that tourists participate in when they visit Alaska is panning for gold A gift shop by the panning center sells blocks of cl class=

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ogorwyne

There is no statistical and significant evidence that the true block is less than 0.20

The question says that 1 in 5 blocks contain gold

p = proportion

= 1/5 = 0.20

We have to form the hypothesis

H0: p = 0.20

H1: p < 0.20

Size of block = 50

50 blocks have 8 blocks of Gold

P = 8/50

= 0.16

Q = 1-P

= 1- 0.16 = 0.84

The Z test statistics is  to be used here

[tex]z = \frac{|P-p|}{\sqrt{\frac{PQ}{n} } } \\\\ \frac{|0.16-0.20|}{\sqrt{\frac{0.16*0.84}{50} } }[/tex]

= 0.771

The value of Z calculated is 0.771

Next you have to find Z tabulated using 10 percent CI

Z tab = 1.645

0.771 < 1.645

What is the Decision rule?

We have to reject the nul hypothesis and accept that the true proportion that contains gold is 0.20. There is no evidence that it is less than 0.20

Read more on probability here: https://brainly.com/question/24756209

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