Write an equation of a line through (5,6) and perpendicular to the line through (4,8) and (-2,-18). please help, will mark brainliest. You also get 10 points

Respuesta :

Answer:

y = 4 1/3x+ 6  

Step-by-step explanation:

Step 1. The slope-intercept form is given as y=mx+b where m is the slope and b is the y-intercept. The y-intercept occurs at x=0 or point (0,b).

-18 -8 / -2 - 4 =  -26 / -6  = 4 1/3  perp = - 4 1/3  =  y=4 1/3 x+b

Step 2. -18 -8 / -2 - 4 =  -26 / -6  = 4 1/3  perp = - 4 1/3  is a vertical line or parallel to the y-axis. So a line perpendicular to x= 4 1/3  is a horizontal line parallel to the x-axis.

Step 3. Therefore y= 4 1/3  is a horizontal line parallel to the x-axis. Now, the line needs to pass through point (5,6) or x=5 and y=6. Then, y=b=6 or y=6 is the equation of the line. but then  x = 4 1/3   so y = 4 1/3x + 6  

Step 4. ANSWER: The equation is  y = 4 1/3x+ 6  where slope m=4 1/3 and y intercept b=6.