delaney1765
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The expression 1/2mv^2 gives the kinetic energy, in joules, have an object with a mass of m kilogram traveling at a speed of v meters per second. What is the kinetic energy of an experimental unmanned jet with a mass of 1.6 times 10^3 kg traveling at a speed of about 3.2 times 10^3 m/s

Respuesta :

Answer: 8,192,000,000 KE in joules. I think

Step-by-step explanation:

1.6 x 10^3 = 1600

3.2 x 10^3 = 3200

3200^2 = 10240000

1600 x 10240000 = 1.6384E10

so then multiply that by 1/2 = 8,192,000,000 KE in joules

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