sorry here is the question!! please help and Thank you!!

Answer:
B. 4
Step-by-step explanation:
[tex] \dfrac{\sqrt{32}}{\sqrt{2}} = [/tex]
[tex] = \dfrac{\sqrt{16 \times 2}}{\sqrt{2}} [/tex]
[tex] = \dfrac{\sqrt{16} \times \sqrt{2}}{\sqrt{2}} [/tex]
[tex] = \dfrac{4\sqrt{2}}{\sqrt{2}} [/tex]
[tex] = 4[/tex]