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find the horizontal and vertical asymptotes of the graph of the function f(x) = 2x^2+1/3x-5​

Respuesta :

Answer:

HA= None VA= 5/3

Step-by-step explanation:

The HA is none because the bottom part is missing x squared so you add x squared and it will be 2/0 which means it's not possible which means HA= none. VA is 5/3 because you set the denominator to 0 so you add 5 then divide by 3 so the answer for VA is 5/3