Helppppp please answer 30 pointssss

Answer:
[tex] \frac{x}{3} = \frac{7x}{12x - 15} \\ 12 {x}^{2} - 15x = 21x \\ 12 {x}^{2} -36x = 0 \\ 12x(x - 3) = 0 \\ \boxed{x = 0} \: or \: \boxed{x = 3} \\ \\ \frac{25 - 3x}{x + 5} = 1 \\ 25 - 3x = x + 5 \\ 3x + x = 25 - 5 \\ 4x = 20 \\ \boxed{ x = 5} \\ \\ \frac{3x - 2}{x} = - \frac{8}{x} \\ 3 {x}^{2} - 2x = - 8x \\ 3 {x}^{2} -6x = 0 \\ 3x(x - 2) = 0 \\ \boxed{x = 0} \: or \: \boxed{x = 2} \\ \\ \frac{3 - x}{x} = \frac{x + 1}{2x} \\ 6x - 2 {x}^{2} = {x}^{2} + x \\ 3 {x}^{2} - 5x = 0 \\ x(3x - 5) = 0 \\ \boxed{x = 0} \: or \: \boxed{x = \frac{5}{3} }[/tex]