A small smooth ring R of weight 8.5N is threaded on a light inextensible string. The ends of the
string are attached to fixed points A and B, with A vertically above B. A horizontal force of magnitude
15.5N acts on R so that the ring is in equilibrium with angle ARB = 90◦. The part AR of the string
makes an angle q with the horizontal and the part BR makes an angle q with the vertical (see diagram).
The tension in the string is T N. Show that T sin q = 12 and T cos q = 3.5 and hence find q.