contestada

In 1971, U.S. astronaut David Scott conducted a simple yet famous experiment on the
surface of the moon, where gm = 1.62 m/s² is the magnitude of the gravitational
acceleration, and there is no atmosphere. Specifically, he dropped a hammer and a feather
from rest at the same height above the ground. Assuming that he released the hammer
from a height 1.55 m above the moon's surface, how fast was the hammer moving when
it hit the ground?
A) 0.98 m/s
B) 1.38 m/s
C) 1.91 m/s
D) 2.24 m/s
E) 5.02 m/s

Respuesta :

Answer:

1.38 m/s

Explanation:

h= Vo.t -1/2 gt^2              h= hi-hf = 0-1.55m = -1.55m

-1.55= Vo.t - 1/2 g.t^2       Vo= is not given so is 0

-1.55 = -1/2 g.t^2

-1.55= -1/2 (1.62 m/s^2) . t^2

t^2 = -1.55 m / -0.81 m /s^2

t^2 = 1.91 m^2/s^2

t= 1.38 m/s

Otras preguntas