Respuesta :

Answer:

[tex]distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } \\ \sqrt{ {28 - 28)}^{2} + {(6 - - 12)}^{2} } \\ \sqrt{ {0}^{2} + {18}^{2} } \\ = \sqrt{ {18}^{2} } = 18unit \\ thank \: you[/tex]