Answer:
V = 6.29 m/s
Explanation:
Given that,
The mass of an automobile, m₁ = 640 kg
The mass of parked car, m₂ = 935 kg
The speed of automobile, u₁ = 55.8 km/h = 15.5 m/s
The speed of the parked car, u₂ = 0
We need to find the speed of the two cars just after they collide . Let V is a common speed. Using the conservation of linear momentum to find it such that,
[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{640\times 15.5}{(640+935)}\\\\V=6.29\ m/s[/tex]
So, the speed of the two cars is equal to 6.29 m/s.
