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The difference between two numbers is 7. The sum of three times the larger number and twice the smaller number is 16.
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Answer:

28 and 12 . (QUORA)

Step-by-step explanation:

Let’s write this down. We are looking for X and Y.

The difference between two numbers is 16: −=16

Three times the larger number is seven times the smaller:  ∗3=∗7

So, we need to solve X and Y from these two equations.

If we re-arrange X*3 = Y*7, we get Y = X*3/7.

So, −∗3/7=16 .  −∗3/7  is the same as  7∗/7−3∗/7 , or  4∗/7 . So  4∗/7=16−>4∗=7∗16−>=7∗4=28 .

Then we just go back to  −=16 , and  =28 , gives us  28−=16,  or  =28–16−>=12 .

So the numbers are 28 and 12.

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