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The equation can be used to find the approach velocity v (in feet per second) of a pole-vaulter and where h represents the height a pole-vaulter can reach. Erwin and Elmer are pole-vaulters. In one of the events they participated, Erwin’s approach velocity was 40 feet per second while Elmer’s approach velocity was 35 per second. Who reached greater height? Justify your answer.

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buchinnamani208

Missing part of question:

A pole-vaulter’s approach velocity v (in feet per second) and height reached h (in feet) are related by the following equation.

v=8√h

Answer:

Erwin

Step-by-step explanation:

The equation is

v=8√h

If velocity is 40 feet per second,

40=8√h

√h=40/8

h=√5

height =2.2360ft

If velocity = 35 feet per second,

v=8√h

35=8√h

√h=35/8

√h= 4.375

height =2.09ft

Therefore Erwin reached greater height =2.2360ft

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