Answer:
[tex]111.3\ \text{square units}[/tex]
Step-by-step explanation:
[tex]PQ=20\ \text{units}[/tex]
[tex]PR=12\ \text{units}[/tex]
[tex]\angle QPR=68^{\circ}[/tex]
[tex]\angle PQR=36^{\circ}[/tex]
Area of the triangle is given by
[tex]A=\dfrac{1}{2}\times PQ\times PR\times\sin \angle QPR\\\Rightarrow A=\dfrac{1}{2}\times 20\times 12\times \sin68^{\circ}\\\Rightarrow A=111.26\approx 111.3\ \text{square units}[/tex]
The area of the triangle is [tex]111.3\ \text{square units}[/tex].
