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The two parents shown in (Figure 1) exert upward forces
of Fi = 18 N on the left end of the plank and F2 = 65 N
on the right end.

How much does the child weigh?

The two parents shown in Figure 1 exert upward forces of Fi 18 N on the left end of the plank and F2 65 N on the right end How much does the child weigh class=

Respuesta :

rafaleo84

Answer:

W = 83 [N] (weight)

Explanation:

We must clarify that the system is in static equilibrium, in such a way that we must perform a sum of forces on the Y-axis equal to zero, in order to determine the downward force corresponding to the weight of the child.

∑Fy = 0

[tex]F_{1}+F_{2}-m*g=0\\18+65=m*g\\m*g = 83 [N][/tex]

And the mass can be determined as follows:

[tex]m*g=83\\m = 83/9.81\\m=8.46[kg][/tex]

Lanuel

The weight of the child is equal to 83 Newton.

Given the following data:

  • Upward force 1 = 18 Newton
  • Upward force 2 = 65 Newton

To determine the weight of the child:

From the diagram, we can deduce that the system is in static equilibrium. Thus, we would resolve the horizontal component of the forces, in order to determine the downward force (weight of child).

Mathematically, the horizontal component of the forces is given by:

[tex]\sum F_y = 0\\\\F_1 +F_2 -mg=0[/tex]

Substituting the given parameters into the formula, we have;

[tex]18+65-mg=0\\\\83=mg[/tex]

Note: Weight = mg

Weight of child = 83 Newton.

Read more: https://brainly.com/question/366299

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