A pole that is 3.3 m tall casts a shadow that is 1.4 m long. At the same time, a nearby building casts a shadow that is 47.5 m long. How tall is the building?
Round your answer to the nearest meter.

If you were to draw a diagram, you could form two similar triangles using the pole and the building (unsolvable otherwise). Since these triangles are similar, we can write the following proportion:

[tex]\frac{3.3}{1.4}=\frac{h}{47.5}[/tex], where [tex]h[/tex] is the height of the building.

Solving, we get:

[tex]h=\frac{47.5\cdot 3.3}{1.4},\\h\approx \fbox{$112\:\mathrm{m}$}[/tex] (rounded to the nearest meter as requested in the problem).

I've drawn the figure below for reference:

A pole that is 3.3 m tall casts a shadow that is 1.4 m long. At the same time, a nearby building casts a shadow that is 47.5 m long. How tall is the building? Round your answer to the nearest meter.

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A pole that is 3.3 m tall casts a shadow that is 1.4 m long. At the same time, a nearby building casts a shadow that is 47.5 m long. How tall is the building?
Round your answer to the nearest meter.