meganpearson199 meganpearson199

25-10-2016
Mathematics

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What is the value of 4a3 – 2b2 + 5 when a = 3 and b = −2?

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25-10-2016

4a(3)-2b(2)+5
4(3)(3)-2(-2)(2)+5
12(3)-(-4)(2)+5
36-(-8)+5
44+5
49
The answer is 49.

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Аноним Аноним

25-10-2016

4a3 – 2b2 + 5

= 4 * 3^3 - 2 * (-2)^2 + 5

= 4 * 27 - 2 * 4 + 5

= 96 - 8 + 5

= 93

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