What is the y-value in the solution to this system of linear equations?

4x + 5y = −12

-2x + 3y = −16

A: −4
B: −2
C: 2
D: 5

Respuesta :

4x+5y=-12 (1)
-4x+6y=-32 (2)
(1)+(2)=> 11y=-44
y=-4
so A : -4

Answer:

Option A is correct that is y = -4

Step-by-step explanation:

Given System of Equations are ,

4x + 5y = -12 ...............(1)

-2x + 3y = -16 .................(2)

To find: value of y in the solution.

We solve it by substitution method,

from equation (1)

[tex]4x =-12-5y[/tex]

[tex]x=\frac{-12-5y}{4}[/tex]

Put this value of x in equation (2)

[tex]-2(\frac{-12-5y}{4})+3y=-16[/tex]

[tex]\frac{12+5y}{2}+3y=-16[/tex]

[tex]\frac{12+5y+6y}{2}=-16[/tex]

[tex]12+11y=-32[/tex]

[tex]11y=-32-12[/tex]

[tex]11y=-44[/tex]

[tex]y=-4[/tex]

Therefore, Option A is correct that is y = -4.