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Pushing on the pump of a bottle of hand washing solution compresses a small spring which obeys Hooke's Law. If the potential energy of the spring is 0.0030 J when the spring is compressed 0.47 cm, determine the following.
(a) force constant of the spring

Respuesta :

Edufirst
Hooke's Law: F = - k x

Potential energy, PE = [1/2] k x^2 = [1/2] kx x = [kx][x/2] = -Fx/2

F = - 2*PE / x = - 2*0.0030J / 0.0047m = -1.28 N (the negative sigh indicates that the force is opposed to the displacement of the spring)


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