A cylinder of argon gas contains 50.0 L of Ar at 18.4 atm and 127 °C. How many moles of argon are in the cylinder?
Number moles of Argon : 28.03
Further explanation
Given
The volume of gas=50 L
P = 18.4 atm
T = 127+273=400 K
Required
moles of Argon
Solution
Use ideal gas Law :
[tex]\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{18.4\times 50}{0.08205\times 400}\\\\n=28.03[/tex]
