Answer:
We conclude that:
[tex]-\frac{1}{12}\cdot \frac{6}{7}=-\frac{1}{14}[/tex]
Hence, option (A) is true.
Step-by-step explanation:
Let us solve the expression
Let us solve the L.H.S to check whether it becomes equal to R.H.S
[tex]-\frac{1}{12}\:\times \frac{6}{7}[/tex]
Factor the number: 12=6×2
[tex]-\frac{1}{6\cdot \:2}\cdot \frac{6}{7}[/tex]
Cross - cancel the common factor
[tex]-\frac{1}{2}\cdot \frac{1}{7}[/tex]
[tex]\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}[/tex]
[tex]-\frac{1\cdot \:1}{2\cdot \:7}[/tex]
Multiply the number: 7×2 = 14
[tex]-\frac{1}{14}[/tex]
Therefore, we conclude that:
[tex]-\frac{1}{12}\cdot \frac{6}{7}=-\frac{1}{14}[/tex]
Hence, option (A) is true.
