Answer:
[tex]Probability = \frac{1}{6}[/tex]
Step-by-step explanation:
Given
The above table
Required
Determine the probability of a sum that is a multiple of 6
Represent the event that an outcome is a multiple of 6 with M.
List out all possible values of M
[tex]M = \{6,6,6,6,6,12\}[/tex]
Number of M is
[tex]n(M) = 6[/tex]
Total possible outcome is:
[tex]n(Total) = 36[/tex]
The theoretical probability is then calculated as follows:
[tex]Probability = \frac{Number\ of\ desired\ outcomes}{Number\ of\ possible\ outcomes}[/tex]
In this case, it is:
[tex]Probability = \frac{n(M)}{n(Total)}[/tex]
[tex]Probability = \frac{6}{36}[/tex]
Simplify fraction
[tex]Probability = \frac{1}{6}[/tex]
