A loan of $36,000 is made at 6.75% interest, compounded annually. After how many years will the amount due reach $57,000 or more?

Respuesta :

Answer:

After 7.04 years the amount will reach $57,000 or more

Step-by-step explanation:

The rule of the compound interest is [tex]A=P(1+\frac{r}{n})^{nt}[/tex] , where

  • A is the new value
  • P is the initial value
  • r is the rate in decimal
  • n is the period of the time
  • t is the time

∵ A loan of $36,000 is made at 6.75% interest, compounded annually

P = 36,000

r = 6.75% = 6.75 ÷ 100 = 0.0675

n = 1 ⇒ compounded annually

∵ The amount after t years will reach $57,000 or more

A = 57,000

→ To find t substitute these values in the rule above

∵ 57,000 = 36,000 [tex](1+\frac{0.0675}{1})^{(1)(t)}[/tex]

∴ 57,000 = 36,000 [tex](1.0675)^{t}[/tex]

→ Divide both sides by 36,000

∵ [tex]\frac{19}{12}[/tex] =  [tex](1.0675)^{t}[/tex]

→ Insert ㏒ in both sides

∴ ㏒( [tex]\frac{19}{12}[/tex] ) = ㏒ [tex](1.0675)^{t}[/tex]

→ Remember ㏒[tex]a^{n}[/tex] = n ㏒([tex]a[/tex])

∵ ㏒( [tex]\frac{19}{12}[/tex] ) = t ㏒(1.0675)

→ Divide both sides by ㏒(1.0675)

∴ 7.035151337 = t

t ≅ 7.04

After 7.04 years the amount will reach $57,000 or more