Answer:
[tex]g=1.81\ m/s^2[/tex]
Explanation:
Mass of Jupiter's moon, [tex]M=8.94\times 10^{22}\ kg[/tex]
Radius, R = 1815 km
We need to find the acceleration due to gravity on the surface of Juptiter's moon. The formula for the acceleration due to gravity is given by :
[tex]g=\dfrac{GM}{R^2}[/tex]
G is universal gravitational constant
[tex]g=\dfrac{6.67\times 10^{-11}\times 8.94\times 10^{22}}{(1815\times 10^3)^2}\\\\g=1.81\ m/s^2[/tex]
So, the acceleration due to gravity on the Jupiter's moon is [tex]1.81\ m/s^2[/tex].
