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Give a systematic name for the following compound: CH3CH2CHCH2CHCH3, with a CH3 group attached to the third (from left to right) carbon and a Br atom attached to the fifth carbon.

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jamesesther1234

Answer:

2-bromo-4 methylheane

Explanation:

Numbering from right to left, the bromine atom falls on the second (2) carbon, while the methyl branch on the 4th.

The systematic naming (IUPAC) of haloalkanes follows the alphabetical rule in naming the substituents, be it alkyl  groups or halogens.

I hope the explanation would suffice.

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