A climber trekked to the top of Mount Everest, elevation 29,035 ft. From a starting point of 24976 ft. In a time of 15 hr, 35 min. Determine the average rate of climb in:(a) miles per minute

Respuesta :

Answer:

The average rate of climb in miles per minute is 8.2x10⁻⁴ miles/min.

Explanation:

The average rate can be calculated as follows:

[tex] \overline{v} = \frac{y_{f} - y_{0}}{t_{f} - t_{0}} [/tex]

Where:

[tex]y_{0}[/tex]: is the initial height = 24976 ft

[tex]y_{f}[/tex]: is the final height = 29035 ft

[tex]t_{0}[/tex]: is the initial time = 0

[tex]t_{f}[/tex]: is the final time = 15 hr, 35 min = 935 min      

Then, the average rate of climb in miles per minute is:

[tex] \overline{v} = \frac{y_{f} - y_{0}}{t_{f} - t_{0}} [/tex]

[tex] \overline{v} = \frac{29035 ft - 24976 ft}{935 min - 0} = 4.34 \frac{ft}{min}*\frac{1 mile}{5280 ft} = 8.2 \cdot 10^{-4} miles/min [/tex]      

Therefore, the average rate of climb in miles per minute is 8.2x10⁻⁴ miles/min.

I hope it helps you!