Answer:
t =2654.01465 year
Step-by-step explanation:
Given that the half-life of carbon-14 is 5600 years and if a piece of charcoal made from the wood of a tree shows only 72% of the carbon-14 expected in living matter.
we know
[tex]y=a(b)^{t/h}[/tex]
where y= final amount
a= initial amount
b= growth/decay
t= time elapsed
h= half time
plugging the values we get
[tex]0.72 =(\frac{1}{2})^{t/5600}\\[/tex]
taking log on both side
log 0.72 = t/5600 log(1/2)
solving we get t =2654.01465 year
