Answer:
28 ways
Step-by-step explanation:
After placing 1 ball in each of the seven bins, there are two balls left.
If we place both balls in a single bin, there are 7 different ways to place the balls (place both on bins 1 through 7).
If we place each of the remaining balls in a different bin, the number of ways to place the balls is:
[tex]n_2=\frac{7!}{(7-2)!2!}=7*3=21[/tex]
The total number of ways to distribute those balls is 21 + 7 = 28 ways.
