Answer:
1.6×10⁻⁶ N.
Explanation:
From the question,
F = (V/r)q......................... Equation 1
Where F = Electric force on the raindrop, V = Potential difference between the base of the cloud and the ground, r = distance between the base of the cloud and the ground, q = the charge on a rain drop.
Given: V = 200MV = 200×10⁶ V, r = 500 m, q = 4.0×10⁻¹² C.
Substitute these values into equation 1
F = [(200×10⁶ )/500]×4.0×10⁻¹²
F = 1.6×10⁻⁶ N.
This question involves the concepts of potential difference and Columb's law.
The electrical force on the raindrop will be "A. 1.6 x 10⁻⁶ N".
According to Columb's Law the electrical force on the raindrop can be given by the following formula:
[tex]F=\frac{kq_1q_2}{r^2}[/tex]------ equation (1)
where,
Now, the potential difference between cloud and ground can be given by the following formula:
[tex]V=\frac{kq_1}{r}[/tex]
substituting this value in equation (1), we get:
[tex]F=\frac{Vq_2}{r}[/tex]
using values:
[tex]F=\frac{(2\ x\ 10^8\ V)(4\ x\ 10^{-12}\ C)}{500\ m}[/tex]
F = 1.6 x 10⁻⁶ N
Learn more about Columb's Law here:
https://brainly.com/question/15707233
