Answer:
A.) 64°
B) 116°
C.) 32°
Step-by-step explanation:
Given that ΔDEG and ΔEGF are isosceles ;
∠EDG = 64º
Therefore ∠EDG = ∠DGE = 64º (Base Angle of an isosceles triangle are equal)
B.) ∠EGF + ∠DGE =180° (SUM OF ∠s on a straight line)
∠EGF + 64° = 180°
∠EGF = (180 - 64) = 116°
C.) x° = ∠EDG (BASE angles of an isosceles triangle are the same)
2x° + 116° = 180° (sum of angles in a triangle)
2x = 64°
x = 32°
