A motorcycle has a speed of 30 m / s. After braking, it decelerates with constant deceleration A = -3.0 m / s ^ 2

Calculates its speed after 3.0 s

Respuesta :

[tex]a = \displaystyle\frac{v-u}{t}[/tex]

[tex]-3 = \displaystyle\frac{v - 30}{3}[/tex]

[tex]v -30 = -9[/tex]

[tex] v = 21 m/s[/tex]

Answer:21

Explanation: