Answer:
FE = 1.17*10^12 N
Explanation:
The magnitude of the electric force is given by the following formula:
[tex]F_E=k\frac{q_1q_2}{r^2}[/tex] ( 1 )
q1 = 3.5C
q2 = 6C
r = 0.4m
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
You replace the values of q1, q2, r and k in the expression (1):
[tex]F_E=(8.98*10^9Nm^2/C^2)\frac{(3.5C)(6C)}{(0.4m)^2}\\\\F_E=1.17*10^{12}N[/tex]
hence, the magnitude of the electric force is 1.17*10^12 N
