Can someone please help ASAP (solving rational equations)

[tex] \dfrac 1 2 = \dfrac 1 x - \dfrac{1}{2x^2}[/tex]
Multiply both sides by 2x²,
[tex]x^2 = 2x - 1[/tex]
[tex]x^2 - 2x + 1 = 0[/tex]
[tex](x - 1)^2 = 0[/tex]
[tex]x - 1 = 0[/tex]
[tex]x=1[/tex]
Answer: C. x=1